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To split a string by a regular expression, pass a regex as a parameter to the split() method, e.g. str. split(/[,. \s]/) . The split method takes a string or regular expression and splits the string based on the provided separator, into an array of substrings.
You do not only have to use literal strings for splitting strings into an array with the split method. You can use regex as breakpoints that match more characters for splitting a string.
If you want to split a string that matches a regular expression (regex) instead of perfect match, use the split() of the re module. In re. split() , specify the regex pattern in the first parameter and the target character string in the second parameter. An example of split by consecutive numbers is as follows.
Split(String) Splits an input string into an array of substrings at the positions defined by a regular expression pattern specified in the Regex constructor. public: cli::array <System::String ^> ^ Split(System::String ^ input); C# Copy.
I suggest
l = re.compile("(?<!^)\s+(?=[A-Z])(?!.\s)").split(s)
Check this demo.
You could use a lookahead:
re.split(r'[ ](?=[A-Z]+\b)', input)
This will split at every space that is followed by a string of upper-case letters which end in a word-boundary.
Note that the square brackets are only for readability and could as well be omitted.
If it is enough that the first letter of a word is upper case (so if you would want to split in front of Hello as well) it gets even easier:
re.split(r'[ ](?=[A-Z])', input)
Now this splits at every space followed by any upper-case letter.
Your question contains the string literal "\b[A-Z]{2,}\b",
but that \b will mean backspace, because there is no r-modifier.
Try: r"\b[A-Z]{2,}\b".
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