Split Integer into two separate Integers

Question

Suppose I have

int n=123456;
int x,y=0;

How do I split the integer "n" in two half.

Note : The Total Number of digits in n will always be multiple of 2, e.g. 1234, 4567, 234567, 345621 etc... all have 2,4,6,8 digits. I want to divide them in half.

I am trying with following Code but it's not working, the y variable is holding reversed second part somehow.

int x, y=0, len, digit;
int n=123456;

len=floor(log10(abs(n))) + 1;
x=n;
while((floor(log10(abs(x))) + 1)>len/2)
{
    digit=x%10;
    x=x/10;
    y=(y*10)+digit;
}
printf("First Half = %d",x);
printf("\nSecond Half = %d",y);

When Input is :

n=123456;

Output I am getting :

First Half = 123
Second Half = 654

Output I want :

First Half : 123

Second Half : 456

Answer 1

Here is a demonstrative program. It does not use any function except printf.:) Thus it is the simplest solution.

#include <stdio.h>

int main( void )
{
    unsigned int a[] = { 12, 1234, 123456, 12345678, 1234567890 };
    const unsigned int Base = 10;

    for ( size_t i = 0; i < sizeof( a ) / sizeof( *a ); i++ )
    {   
        unsigned int divisor = Base;
        while ( a[i] / divisor > divisor ) divisor *= Base;

        printf( "%u\t%u\n", a[i] / divisor, a[i] % divisor );
    }        
}

The program output is

1       2
12      34
123     456
1234    5678
12345   67890

If you are going to use a signed integer type and negative numbers then the program can look the following way

#include <stdio.h>

int main( void )
{
    int a[] = { -12, 1234, -123456, 12345678, -1234567890 };
    const int Base = 10;

    for ( size_t i = 0; i < sizeof( a ) / sizeof( *a ); i++ )
    {   
        int divisor = Base;
        while ( a[i] / ( a[i] < 0 ? -divisor : divisor ) > divisor ) divisor *= Base;

        printf( "%d\t%d\n", a[i] / divisor, a[i] % divisor );
    }        
}

Its output is

-1      -2
12      34
-123    -456
1234    5678
-12345  -67890

Answer 2

Here is actually what I would do

#include <stdio.h>
#include <math.h>

int main(void)
{
  int x, y=0, len, digit;
  int n=123456;

  len=floor(log10(abs(n))) + 1;
  x = n / pow(10, len / 2);
  y = n - x * pow(10, len / 2;
  printf("First Half = %d",x);
  printf("\nSecond Half = %d",y);
}