Menu
What is the best way to split a list into parts based on an arbitrary number of indexes? E.g. given the code below
indexes = [5, 12, 17] list = range(20) return something like this
part1 = list[:5] part2 = list[5:12] part3 = list[12:17] part4 = list[17:] If there are no indexes it should return the entire list.
874
Use the str. split() method to split the string into a list. Access the list element at the specific index. Assign the result to a variable.
Use split() method to split by delimiter. If the argument is omitted, it will be split by whitespace, such as spaces, newlines \n , and tabs \t . Consecutive whitespace is processed together. A list of the words is returned.
Usually, we use a comma to separate three items or more in a list. However, if one or more of these items contain commas, then you should use a semicolon, instead of a comma, to separate the items and avoid potential confusion.
This is the simplest and most pythonic solution I can think of:
def partition(alist, indices): return [alist[i:j] for i, j in zip([0]+indices, indices+[None])] if the inputs are very large, then the iterators solution should be more convenient:
from itertools import izip, chain def partition(alist, indices): pairs = izip(chain([0], indices), chain(indices, [None])) return (alist[i:j] for i, j in pairs) and of course, the very, very lazy guy solution (if you don't mind to get arrays instead of lists, but anyway you can always revert them to lists):
import numpy partition = numpy.split If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
