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Specifying distinct sequence per table in Hibernate on subclasses

Is there a way to specify distinct sequences for each table in Hibernate, if the ID is defined on a mapped superclass?

All entities in our application extend a superclass called DataObject like this:

@MappedSuperclass
public abstract class DataObject implements Serializable {
    @Id 
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    @Column(name = "id")
    private int id;
}

@Entity
@Table(name = "entity_a")
public class EntityA extends DataObject { ... }

@Entity
@Table(name = "entity_b")
public class EntityB extends DataObject { ... }

This causes all entities to use a shared sequence, the default hibernate_sequence.

What I would like to do is use a separate sequence for each entity, for example entity_a_sequence and entity_b_sequence in the example above. If the ID were specified on the subclasses then I could use the @SequenceGenerator annotation to specify a sequence for each entity, but in this case the ID is on the superclass. Given that ID is in the superclass, is there a way I can use a separate sequence for each entity — and if so, how?

(We are using PostgreSQL 8.3, in case that's relevant)

like image 271
gutch Avatar asked Dec 30 '10 07:12

gutch


3 Answers

Have you tried doing it this way ?

@MappedSuperclass
public abstract class DataObject implements Serializable {
    @Id 
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "idgen")
    @Column(name = "id")
    private int id;
}

@Entity
@SequenceGenerator(initialValue = 1, name = "idgen", sequenceName = "entityaseq")
@Table(name = "entity_a")
public class EntityA extends DataObject { 

}

@Entity
@SequenceGenerator(initialValue = 1, name = "idgen", sequenceName = "entitybseq")
@Table(name = "entity_b")
public class EntityB extends DataObject {

}

I'm sorry I don't have the required environment to test it right now but I'll try it later.

like image 75
François Cassin Avatar answered Nov 15 '22 16:11

François Cassin


We use this in the abstract superclass of all of our JPA entities:

@Id
@GeneratedValue(generator = "pooled")
@GenericGenerator(name = "pooled", strategy = "org.hibernate.id.enhanced.TableGenerator", parameters = {
        @org.hibernate.annotations.Parameter(name = "value_column_name", value = "sequence_next_hi_value"),
        @org.hibernate.annotations.Parameter(name = "prefer_entity_table_as_segment_value", value = "true"),
        @org.hibernate.annotations.Parameter(name = "optimizer", value = "pooled-lo"),
        @org.hibernate.annotations.Parameter(name = "increment_size", value = "100")})
private Long id;

It's a bit verbose, but it allows setting the prefer_entity_table_as_segment_value which means you don't need to repeat the id field or the generator annotations in the subclasses.

like image 43
Frans Avatar answered Nov 15 '22 17:11

Frans


I was not quite happy about the need to declare the sequence name on each class individually. I have checked the source code and came up with this solution:

import javax.persistence.Column;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import org.hibernate.annotations.GenericGenerator;
import org.hibernate.annotations.Parameter;
import org.hibernate.id.enhanced.SequenceStyleGenerator;

// ...

@Id
@GeneratedValue(generator = "sequenceIdGenerator")
@GenericGenerator(
        name = "sequenceIdGenerator", 
        strategy = "sequence",
        parameters = @Parameter(
                name = SequenceStyleGenerator.CONFIG_PREFER_SEQUENCE_PER_ENTITY,
                value = "true"))
@Column(updatable = false, nullable = false)
protected Long id;
like image 7
Jens Piegsa Avatar answered Nov 15 '22 15:11

Jens Piegsa