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If I compile a C program with any arm compiler (e.g. arm-none-eabi-gcc) and afterwards call gdb-multiarch with the binary as second paramter, it will correctly determine the machine type and I can debug my remote application.
If however I call gdb-multiarch on its own, it will assume my machine type (x86_64) and tries to debug the remote target with the wrong architecture..
How do I specify the machine type/architecture (e.g. armv5te) in gdb-multiarch?
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The simplest way to configure and build GDB is to run configure from the `gdb- version-number ' source directory, which in this example is the `gdb-5.1. 1' directory. First switch to the `gdb- version-number ' source directory if you are not already in it; then run configure .
gdb-multiarch. GDB is a source-level debugger, capable of breaking programs at any specific line, displaying variable values, and determining where errors occurred. Currently, gdb supports C, C++, D, Objective-C, Fortran, Java, OpenCL C, Pascal, assembly, Modula-2, Go, and Ada. A must-have for any serious programmer.
A target is the execution environment occupied by your program. Often, GDB runs in the same host environment as your program; in that case, the debugging target is specified as a side effect when you use the file or core commands.
The fine manual says:
set architecture archThis command sets the current target architecture to arch. The value of arch can be "
auto", in addition to one of the supported architectures.
This sure sounds like what you're after, to me.
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