We can write a simple get
like this:
import pysftp
hostname = "somehost"
user = "bob"
password = "123456"
filename = 'somefile.txt'
with pysftp.Connection(hostname, username=user, private_key='/home/private_key_file') as sftp:
sftp.get(filename)
However, I want to specify a pattern in the filename, something like: '*.txt'
Any idea on how to do this using pysftp
?
There's no function to download files matching a file mask in pysftp.
You have to:
Connection.listdir
or Connection.walktree
(if you need recursion)Connection.get
individually for each.For a trivial implementation, see:
List files on SFTP server matching wildcard in Python using Paramiko
It's about Paramiko, but the file matching part will be the same with pysftp:
import fnmatch
for filename in sftp.listdir('/remote/path'):
if fnmatch.fnmatch(filename, "*.txt"):
sftp.get("/remote/path/" + filename, "/local/path/" + filename)
Though your should really be using Paramiko anyway: pysftp vs. Paramiko
For a recursive example (you have to add the file matching), see:
Python pysftp get_r from Linux works fine on Linux but not on Windows.
See also how Connection.get_d
or Connection.get_r
are implemented.
Can confirm after going through the documentation that you can't list using a pattern. So i did something like this:
import pysftp
import re
server = pysftp.Connection(host=FTP_HOST,
username=FTP_USERNAME,
password=FTP_PASSWORD)
server.cwd(YOUR_FILES_PATH)
filelist = server.listdir()
for filename in filelist:
filedate = re.search(".*\.txt$", filename)
if filedate:
print "FOUND FILE " + filename
import pysftp
import sys
[...]
dn = datetime.now().strftime("%Y%m%d%H");
with pysftp.Connection(myHost, myUsername, password=myPassword) as sftp:
myFileList = sftp.listdir("files/")
for filename in myFileList:
if (filename.rfind("ArrivalList_" + dn) != -1):
sftp.get("files/" + filename, "/tmp/" + filename)
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