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Specified key is not a valid size for this algorithm

I have with this code:

RijndaelManaged rijndaelCipher = new RijndaelManaged();              // Set key and IV             rijndaelCipher.Key = Convert.FromBase64String("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz012345678912");             rijndaelCipher.IV = Convert.FromBase64String("1234567890123456789012345678901234567890123456789012345678901234"); 

I get throws :

Specified key is not a valid size for this algorithm.  Specified initialization vector (IV) does not match the block size for this algorithm. 

What's wrong with this strings ? Can I count at some examples strings from You ?

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user278618 Avatar asked May 27 '10 07:05

user278618


2 Answers

The string "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz012345678912" when base64-decoded yields 48 bytes (384 bits). RijndaelManaged supports 128, 192 and 256 bit keys.

A valid 128-bit key is new byte[]{ 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F } or if you need to get it from base64 : Convert.FromBase64String("AAECAwQFBgcICQoLDA0ODw==").

The default blocksize is 128 bits, so the same byte-array will work as the IV.

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Rasmus Faber Avatar answered Oct 06 '22 03:10

Rasmus Faber


Use the random number generator class (RNGCryptoServiceProvider) to fill a specified buffer with random bytes as follows:

var numberOfBits = 256; // or 192 or 128, however using a larger bit size renders the encrypted data harder to decipher  var ivBytes = new byte[numberOfBits / 8]; // 8 bits per byte  new RNGCryptoServiceProvider().GetBytes(ivBytes);  var rijndaelManagedCipher = new RijndaelManaged();  //Don't forget to set the explicitly set the block size for the IV if you're not using the default of 128  rijndaelManagedCipher.BlockSize = 256;  rijndaelManagedCipher.IV = ivBytes; 

Note the same process could be used to derive a key. Hope this helps.

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Marcous Osewelle Avatar answered Oct 06 '22 03:10

Marcous Osewelle