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To sort an array of strings in Java, we can use Arrays. sort() function.
C Sort String in Ascending Order Receive any string using gets() function. Get the length of string using strlen() function of string. h library and initialize it to any variable say len. Now create a for loop that runs from 0 to one less than the string length.
Yes. That is definitely possible. You could know that just by writing some sample code, such as this: char charArray[] = {'A','Z', 'K', 'L' }; size_t arraySize = sizeof(charArray)/sizeof(*charArray); std::sort(charArray, charArray+arraySize); //print charArray : it will print all chars in ascending order.
It means that the array sorts elements in the ascending order by using the sort() method, after that the reverseOrder() method reverses the natural ordering, and we get the sorted array in descending order. Syntax: public static <T> Comparator<T> reverseOrder()
This code snippet is working properly
If you have problems with numbers (say 1, 2, 10, 12 which will be sorted 1, 10, 12, 2) you can use LINQ:
var arr = arr.OrderBy(x=>x).ToArray();
Actually I don't see any nulls:
given:
static void Main()
{
string[] testArray = new string[]
{
"aa",
"ab",
"ac",
"ad",
"ab",
"af"
};
Array.Sort(testArray, StringComparer.InvariantCulture);
Array.ForEach(testArray, x => Console.WriteLine(x));
}
I obtained:
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