I'm trying to sort an array that looks like this:
var dateGroups = [
[
{age:20, date: Fri Feb 03 2012 14:30:00 GMT+1100 (EST)},
{age:12, date: Fri Feb 03 2012 18:20:00 GMT+1100 (EST)},
{age:18, date: Fri Feb 03 2012 21:43:00 GMT+1100 (EST)}
],
[
{age:32, date: Fri Feb 01 2012 10:54:00 GMT+1100 (EST)},
{age:44, date: Fri Feb 01 2012 11:45:00 GMT+1100 (EST)},
],
[
{age:22, date: Fri Feb 05 2012 10:54:00 GMT+1100 (EST)},
{age:22, date: Fri Feb 05 2012 18:22:00 GMT+1100 (EST)},
]
]
The objects inside dateGroups' nested arrays are already sorted in ascending order, but I also want to sort the arrays themselves based on the grouped dates.
In this case the array should then look like this:
var dateGroups = [
[
{age:32, date: Fri Feb 01 2012 10:54:00 GMT+1100 (EST)},
{age:44, date: Fri Feb 01 2012 11:45:00 GMT+1100 (EST)},
],
[
{age:20, date: Fri Feb 03 2012 14:30:00 GMT+1100 (EST)},
{age:12, date: Fri Feb 03 2012 18:20:00 GMT+1100 (EST)},
{age:18, date: Fri Feb 03 2012 21:43:00 GMT+1100 (EST)}
],
[
{age:22, date: Fri Feb 05 2012 10:54:00 GMT+1100 (EST)},
{age:22, date: Fri Feb 05 2012 18:22:00 GMT+1100 (EST)},
]
]
The function used to sort should also return the new sorted version of dateGroups.
I've tried using Underscore.js's sortBy()
function but I can't figure out how to sort the arrays based on the value of a property inside one of the objects. Is there a specific way to sort Date objects? Or are they sorted in the same way as numbers or letters?
According to Underscore.js documentation, you should simply write your own iterator for that cause. Something like this:
_.sortBy(dateGroups, function(arrayElement) {
//element will be each array, so we just return a date from first element in it
return arrayElement[0].date.getTime();
});
You can sort them by passing a custom sort function to Array.sort
.
dateGroups.sort(function(a, b) {
return b[0].date.getTime() - a[0].date.getTime();
});
The custom function needs to return a number less than zero (a comes before b), greater than zero (a comes after b) or zero (a and b are equal).
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