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I would like to know how can I sort a string by the number inside.
As example I have:
hello = " hola %d" % (number_from_database)
bye = "adios %d" % (number_from_database_again)
I want to sort them by the number even if it changes.
347
To do this we can use the extra parameter that sort() uses. This is a function that is called to calculate the key from the entry in the list. We use regex to extract the number from the string and sort on both text and number.
Python sorted() Function The sorted() function returns a sorted list of the specified iterable object. You can specify ascending or descending order. Strings are sorted alphabetically, and numbers are sorted numerically. Note: You cannot sort a list that contains BOTH string values AND numeric values.
sort() Method. In Java, Arrays is the class defined in the java. util package that provides sort() method to sort an array in ascending order. It uses Dual-Pivot Quicksort algorithm for sorting.
You can pass a key to sort:
sorted(l, key=lambda x: int(re.sub('\D', '', x)))
For example:
In [1]: import re
In [2]: l = ['asdas2', 'asdas1', 'asds3ssd']
In [3]: sorted(l, key=lambda x: int(re.sub('\D', '', x)))
Out[3]: ['asdas1', 'asdas2', 'asds3ssd']
Where re.sub('\D', '', x) replaces everything but the digits.
140
Just a little complement to Andy's answer.
If you want to sort set which also contain strings without any number:
sorted(l, key=lambda x: int('0'+re.sub('\D', '', x)))
, which would put those strings without any number at the very beginning.
27
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