sort array with integer strings type in jQuery

Question

I have a array of integers of type string.

var a = ['200','1','40','0','3'];

output

>>> var a = ['200','1','40','0','3'];
console.log(a.sort());
["0", "1", "200", "3", "40"]

---

I'll also have a mixed type array. e.g.

var c = ['200','1','40','apple','orange'];

output

>>> var c = ['200','1','40','apple','orange']; console.log(c.sort());
["1", "200", "40", "apple", "orange"]

==================================================
The integers of string type gets unsorted.

Answer 1

This should be what you're looking for

var c = ['200','1','40','cba','abc'];
c.sort(function(a, b) {
  if (isNaN(a) || isNaN(b)) {
    if (a > b) return 1;
    else return -1;
  }
  return a - b;
});
// ["1", "40", "200", "abc", "cba"]

Answer 2

As others said, you can write your own comparison function:

var arr = ["200", "1", "40", "cat", "apple"]
arr.sort(function(a,b) {
  if (isNaN(a) || isNaN(b)) {
    return a > b ? 1 : -1;
  }
  return a - b;
});

// ["1", "40", "200", "apple", "cat"]