Sort array by firstname (alphabetically) in Javascript [duplicate]

Question

I got an array (see below for one object in the array) that I need to sort by firstname using JavaScript. How can I do it?

var user = {    bio: null,    email:  "[email protected]",    firstname: "Anna",    id: 318,    lastAvatar: null,    lastMessage: null,    lastname: "Nickson",    nickname: "anny" }; 

Answer 1

Shortest possible code with ES6!

users.sort((a, b) => a.firstname.localeCompare(b.firstname)) 

String.prototype.localeCompare() basic support is universal!

Answer 2

Suppose you have an array users. You may use users.sort and pass a function that takes two arguments and compare them (comparator)

It should return

• something negative if first argument is less than second (should be placed before the second in resulting array)
• something positive if first argument is greater (should be placed after second one)
• 0 if those two elements are equal.

In our case if two elements are a and b we want to compare a.firstname and b.firstname

Example:

users.sort(function(a, b){     if(a.firstname < b.firstname) { return -1; }     if(a.firstname > b.firstname) { return 1; }     return 0; }) 

This code is going to work with any type.

Note that in "real life"™ you often want to ignore case, correctly sort diacritics, weird symbols like ß, etc when you compare strings, so you may want to use localeCompare. See other answers for clarity.