Socket IO returns 127.0.0.1 as host address and not 192.168.0.* on my device

Question

When I run the following code to determine my device's local IP address, I get 127.0.0.1 instead of 192.168.0.101.

import socket
import threading

PORT = 8080
HOST_NAME = socket.gethostname()
print(HOST_NAME)
SERVER = socket.gethostbyname(HOST_NAME)

print(SERVER)

The output i get on the console is

MyDeviceName.local
127.0.0.1

Answer 1

127.0.0.1 is localhost address, it is right. If you want your device's address do this:

import socket
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.connect(("8.8.8.8", 80))
print(s.getsockname()[0])