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smtplib and gmail - python script problems

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Here's my script:

#!/usr/bin/python  import smtplib msg = 'Hello world.'  server = smtplib.SMTP('smtp.gmail.com',587) #port 465 or 587 server.ehlo() server.starttls() server.ehlo() server.login('[email protected]','mypass') server.sendmail('[email protected]','[email protected]',msg) server.close() 

I'm just trying to send an email from my gmail account. The script uses starttls because of gmail's requirement. I've tried this on two web hosts, 1and1 and webfaction. 1and1 gives me a 'connection refused' error and webfaction reports no error but just doesn't send the email. I can't see anything wrong with the script, so I'm thinking it might be related to the web hosts. Any thoughts and comments would be much appreciated.

EDIT: I turned on debug mode. From the output, it looks like it sent the message successfully...I just never receive it.

send: 'ehlo web65.webfaction.com\r\n' reply: '250-mx.google.com at your service, [174.133.21.84]\r\n' reply: '250-SIZE 35651584\r\n' reply: '250-8BITMIME\r\n' reply: '250-STARTTLS\r\n' reply: '250-ENHANCEDSTATUSCODES\r\n' reply: '250 PIPELINING\r\n' reply: retcode (250); Msg: mx.google.com at your service, [174.133.21.84] SIZE 35651584 8BITMIME STARTTLS ENHANCEDSTATUSCODES PIPELINING send: 'STARTTLS\r\n' reply: '220 2.0.0 Ready to start TLS\r\n' reply: retcode (220); Msg: 2.0.0 Ready to start TLS send: 'ehlo web65.webfaction.com\r\n' reply: '250-mx.google.com at your service, [174.133.21.84]\r\n' reply: '250-SIZE 35651584\r\n' reply: '250-8BITMIME\r\n' reply: '250-AUTH LOGIN PLAIN\r\n' reply: '250-ENHANCEDSTATUSCODES\r\n' reply: '250 PIPELINING\r\n' reply: retcode (250); Msg: mx.google.com at your service, [174.133.21.84] SIZE 35651584 8BITMIME AUTH LOGIN PLAIN ENHANCEDSTATUSCODES PIPELINING send: 'AUTH PLAIN *****\r\n' reply: '235 2.7.0 Accepted\r\n' reply: retcode (235); Msg: 2.7.0 Accepted send: 'mail FROM:<[email protected]> size=12\r\n' reply: '250 2.1.0 OK 4sm652580yxq.48\r\n' reply: retcode (250); Msg: 2.1.0 OK 4sm652580yxq.48 send: 'rcpt TO:<[email protected]>\r\n' reply: '250 2.1.5 OK 4sm652580yxq.48\r\n' reply: retcode (250); Msg: 2.1.5 OK 4sm652580yxq.48 send: 'data\r\n' reply: '354  Go ahead 4sm652580yxq.48\r\n' reply: retcode (354); Msg: Go ahead 4sm652580yxq.48 data: (354, 'Go ahead 4sm652580yxq.48') send: 'Hello world.\r\n.\r\n' reply: '250 2.0.0 OK 1240421143 4sm652580yxq.48\r\n' reply: retcode (250); Msg: 2.0.0 OK 1240421143 4sm652580yxq.48 data: (250, '2.0.0 OK 1240421143 4sm652580yxq.48') 
like image 466
spencewah Avatar asked Apr 22 '09 16:04

spencewah


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2 Answers

Some self-promotion here, but I feel on a valid ground.

You would literally only need this code to do exactly what you wrote:

import yagmail yag = yagmail.SMTP('[email protected]') yag.send('[email protected]', subject = None, contents = 'Hello') 

Or a one liner:

yagmail.SMTP('[email protected]').send('[email protected]', None, 'Hello world.') 

What is nice is that I propose to use keyring to store your password, so you never have a risk of people seeing your password in your script.

You can set this up by running once in your interpreter:

import yagmail yagmail.register("[email protected]", "mypassword") 

and exit. Then you can just use:

import yagmail yagmail.SMTP("[email protected]") # without password 

If you add .yagmail with "[email protected]" in your home dir, then you can just do: yagmail.SMTP(), but that's rather pointless by now.

Warning: If you get serious about sending a lot of messages, better set up OAuth2, yagmail can help with that.

yagmail.SMTP("[email protected]", oauth2_file="/path/to/save/creds.json") 

The first time ran, it will guide you through the process of getting OAuth2 credentials and store them in the file so that next time you don't need to do anything with it. Do you suspect someone found your credentials? They'll have limited permissions, but you better invalidate their credentials through gmail.

For the package/installation please look at git or readthedocs, available for both Python 2 and 3.

like image 169
PascalVKooten Avatar answered Oct 27 '22 08:10

PascalVKooten


Have you tried constructing a valid message?

from email.MIMEText import MIMEText  msg = MIMEText('body') msg['Subject'] = 'subject' msg['From'] = "..." msg['Reply-to'] = "..." msg['To'] = "..." 
like image 42
Toni Ruža Avatar answered Oct 27 '22 07:10

Toni Ruža