Slim Callable UserController does not exist RuntimeException

Question

Hi i am new to slim i stuck on this anyone help please

routes.php

$app->get('/', 'UserController:index');

dependencis.php

$container['src\UserController'] = function ($container) {
    return new \src\UserController($container->get('settings'));
};

UserController.php

namespace App\Controllers;

use Psr\Http\Message\ServerRequestInterface as Request;
use Psr\Http\Message\ResponseInterface as Response;
use App\src\Controller;
class UserController extends Controller {
    public function index(Request $request, Response $response) {
        return $this->db;
    }
}

and controller.php

namespace App\src;

class Controller {
    protected $container;
    public function __construct($c) {
        $this->container = $c;
    }

    public function __get($property) {
        if($this->container->has($property)) {
            return $this->container->get($property);
        }
        return $this->{$property};
    }
}

Answer 1

As you have defined your route as:

$app->get('/', 'UserController:index');

Then you need to define your DI factory as:

$container['UserController'] = function ($container) {
    // return an instantiated UserController here.
};

You should also look up how namespaces and PSR-4's mapping of namespace name to directory work. In general there is never a src in a namespace name, but you do see a namespace such as App mapped to a directory call src in the Composer autoloader as specified in composer.json.

Usually, it looks something like this:

"autoload": {
    "psr-4": {
        "App\\": "src/"
    }
},

This means that you have a directory called src and any class inside that directory, will have a base namespace of App and then any other directories act as sub-namespaces.

i.e. if you have a file called src/Controllers/UserController.php, then the class definition in that file will be:

<?php
namespace App\Controllers;
class UserController
{
    // methods here
}

Note also that the capitalisation of the filename matches the class name and that the capitalisation of the directories match the capitalisation of the sub-namespaces.

To continue the example, I would expect the DI factory to look like this:

$container['UserController'] = function ($container) {
    return new \App\Controllers\UserController($container->get('settings'));
};

It's really unusual to see src in a namespace definition, so go through and check that your namespaces and files on disk all match up as the code in the question is inconsistent.

Answer 2

You can check the name of the file (controller.php) that holds controller class. they must be the same.

for example :

if you have Contoller.php file you must make the name of class like this Controller.

in your example you have Controller.php file with capital letter of C but, the class controller doesn't start with a capital letter.

so, make sure the file name is same as the class name.

hope this will help you .