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I have a C++ function that has 5 arguments, all of which have default values. If I pass in the first three arguments, the program will assign a default value to the last two arguments. Is there any way to pass 3 arguments, and skip one in the middle, giving values to say, the first, second, and fifth arguments?
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Optional arguments are generally not allowed in C (but they exist in C++ and in Ocaml, etc...). The only exception is variadic functions (like printf ).
Default arguments can be skipped from function call.
Variadic functions are functions that can take a variable number of arguments. In C programming, a variadic function adds flexibility to the program. It takes one fixed argument and then any number of arguments can be passed.
It's not possible to skip it, but you can pass the default argument using ReflectionFunction .
Not directly, but you might be able to do something with std::bind:
int func(int arg1 = 0, int arg2 = 0, int arg3 = 0);
// elsewhere...
using std::bind;
using std::placeholders::_1;
auto f = bind(func, 0, _1, 0);
int result = f(3); // Call func(0, 3, 0);
The downside is of course that you are re-specifying the default parameters. I'm sure somebody else will come along with a more clever solution, but this could work if you're really desperate.
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