Skip over iteration in Enumerable#collect

Question

There is method Enumerable#reject which serves just the purpose:

(1..4).reject{|x| x == 3}.collect{|x| x + 1}

The practice of directly using an output of one method as an input of another is called method chaining and is very common in Ruby.

BTW, map (or collect) is used for direct mapping of input enumerable to the output one. If you need to output different number of elements, chances are that you need another method of Enumerable.

Edit: If you are bothered by the fact that some of the elements are iterated twice, you can use less elegant solution based on inject (or its similar method named each_with_object):

(1..4).each_with_object([]){|x,a| a << x + 1 unless x == 3}

I would simply call .compact on the resultant array, which removes any instances of nil in an array. If you'd like it to modify the existing array (no reason not to), use .compact!:

(1..4).collect do |x|
  next if x == 3
  x
end.compact!

Ruby 2.7+

There is now!

Ruby 2.7 is introducing filter_map for this exact purpose. It's idiomatic and performant, and I'd expect it to become the norm very soon.

For example:

numbers = [1, 2, 5, 8, 10, 13]
numbers.filter_map { |i| i * 2 if i.even? }
# => [4, 16, 20]

Here's a good read on the subject.

Hope that's useful to someone!

just a suggestion, why don't you do it this way:

result = []
(1..4).each do |x|
  next if x == 3
  result << x
end
result # => [1, 2, 4]

in that way you saved another iteration to remove nil elements from the array. hope it helps =)