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How to convert a number to string and vice versa in C++
How do I convert an integral value to a string in C++?
This is what I've tried:
for(size_t i = 0;vecServiceList.size()>i;i++)
{
if ( ! vecServiceList[i].empty() )
{
string sService = "\t" + i +". "+ vecServiceList[i] ;
}
}
And here is the error:
invalid operands of types 'const char*' and 'const char [3]' to binary 'operator+'
446
Converting to double will not cause an overflow, but it could result in a loss of precision for a very large size_t value. Again, it doesn't make a lot of sense to convert a size_t to a double ; you're still better off keeping the value in a size_t variable.
Just use casting. You can safely convert size_t to int by checking its range before casting it. If it is outside the valid int range, you can't. Test against INT_MAX to ensure no possible signed integer overflow before casting it.
std::to_string in C++ It is one of the method to convert the value's into string. The to_string() method takes a single integer variable or other data type and converts into the string.
std::string::data() in C++It returns a pointer to the array, obtained from conversion of string to the array. Its Return type is not a valid C-string as no '\0' character gets appended at the end of array. Syntax: const char* data() const; char* is the pointer to the obtained array.
You could use a string stream:
#include <sstream>
...
for (size_t i = 0; ... ; ...)
{
std::stringstream ss;
ss << "\t" << i << vecServiceList[i];
std::string sService = ss.str();
// do what you want with sService
}
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