Simplest way to count words in a file

Question

I'm trying to code in the simplest way a program to count word occurrences in file in Scala Language. So far I have these piece of code:

import scala.io.Codec.string2codec
import scala.io.Source
import scala.reflect.io.File

object WordCounter {
    val SrcDestination: String = ".." + File.separator + "file.txt"
    val Word = "\\b([A-Za-z\\-])+\\b".r

    def main(args: Array[String]): Unit = {

        val counter = Source.fromFile(SrcDestination)("UTF-8")
                .getLines
                .map(l => Word.findAllIn(l.toLowerCase()).toSeq)
                .toStream
                .groupBy(identity)
                .mapValues(_.length)

        println(counter)
    }
}

Don't bother of regexp expression. I would like to know how to extract single words from sequence retrieved in this line:

map(l => Word.findAllIn(l.toLowerCase()).toSeq)

in order to get each word occurency counted. Currently I'm getting map with counted words sequences.

Answer 1

You can turn the file lines into words by splitting them with the regex "\\W+" (flatmap is lazy so it doesn't need to load the entire file into memory). To count occurrences you can fold over a Map[String, Int] updating it with each word (much more memory and time efficient than using groupBy)

scala.io.Source.fromFile("file.txt")
  .getLines
  .flatMap(_.split("\\W+"))
  .foldLeft(Map.empty[String, Int]){
     (count, word) => count + (word -> (count.getOrElse(word, 0) + 1))
  }