Simple Structs program in C

Question

I'm new to programming so please bear with me. Can anyone please explain what the last line of code is doing and what this entire block of code trying to do. I know the first block is creating a structure called node and adding two pointers *next and *prev to it. btw this is a part of a linked list program

struct node
 {
  char line[80];
  struct node *next,*prev;
 };

struct node *start=NULL,*temp,*temp1,*temp2,*newnode;

Thank you in advance.

Answer 1

struct node *start=NULL,*temp,*temp1,*temp2,*newnode;

can be as

struct node *start=NULL;
struct node  *temp;
struct node *temp1;
struct node *temp2;
struct node *newnode;

Now is it easy to understand..?

Answer 2

The last line is creating 5 pointers of type struct node namely start which is pointing to NULL, temp, temp1, temp2 and newnode.

The whole block of code is actually creating a struct called node which contains an array of 80 characters, followed by pointers to next and previous. Hence it is creating a structure for a doubly linked list.