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For the ruby .times do is there a counter or do I have to do the following
count = 0
4.times do
puts "this is the count #{count}"
count = count+1
655
In Ruby, for loops are used to loop over a collection of elements. Unlike a while loop where if we're not careful we can cause an infinite loop, for loops have a definite end since it's looping over a finite number of elements.
In Ruby, we use a break statement to break the execution of the loop in the program. It is mostly used in while loop, where value is printed till the condition, is true, then break statement terminates the loop. In examples, break statement used with if statement. By using break statement the execution will be stopped.
The times function in Ruby returns all the numbers from 0 to one less than the number itself. It iterates the given block, passing in increasing values from 0 up to the limit. If no block is given, an Enumerator is returned instead.
This means that the loop will run forever ( infinite loop ). To stop this, we can use break and we have used it. if a == "n" -> break : If a user enters n ( n for no ), then the loop will stop there. Any other statement of the loop will not be further executed.
Yes, times yields a counter:
4.times do |count|
puts "this is the count #{count}"
end
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