Showing a Windows form on a secondary monitor?

Question

I'm trying to set a Windows Form on secondary monitor, as follows:

private void button1_Click(object sender, EventArgs e)
{
    MatrixView n = new MatrixView();
    Screen[] screens = Screen.AllScreens;
    setFormLocation(n, screens[1]);
    n.Show();
}

private void setFormLocation(Form form, Screen screen)
{
    // first method
    Rectangle bounds = screen.Bounds;
    form.SetBounds(bounds.X, bounds.Y, bounds.Width, bounds.Height);

    // second method
    //Point location = screen.Bounds.Location;
    //Size size = screen.Bounds.Size;

    //form.Left = location.X;
    //form.Top = location.Y;
    //form.Width = size.Width;
    //form.Height = size.Height;
}

The properties of bounds seem correct, but in both methods I've tried, this maximizes the form on the primary monitor. Any ideas?

Answer 1

this.Location = Screen.AllScreens[1].WorkingArea.Location;

this is the Form reference.

Answer 2

Try setting StartPosition parameter as FormStartPosition.Manual inside your SetFormLocation method.

Answer 3

@Gengi's answer is succinct and works well. If the window is maximised it does not move the window. This snippet solves that (although I suspect the windows "normal" dimensions must be smaller than the new screen dimensions for this to work):

    void showOnScreen(int screenNumber)
    {
        Screen[] screens = Screen.AllScreens;

        if (screenNumber >= 0 && screenNumber < screens.Length)
        {
            bool maximised = false;
            if (WindowState == FormWindowState.Maximized)
            {
                WindowState = FormWindowState.Normal;
                maximised = true;
            }
            Location = screens[screenNumber].WorkingArea.Location;
            if (maximised)
            {
                WindowState = FormWindowState.Maximized;
            }
        }
    }