Show iPhone soft keyboard even though a hardware keyboard is connected

Question

My iPad app uses an external "device" that acts as a hardware keyboard. But, at some point in the settings, I need to input text and I can't use the "device" ("device" is not a keyboard). So, is there any way to force pop the soft keyboard even thought I have a hardware keyboard connected?

Answer 1

Yes. We've done this in a few of our apps for when the user has a Bluetooth scanner "keyboard" paired with the device. What you can do is make sure your textField has an inputAccessoryView and then force the frame of the inputAccessoryView yourself. This will cause the keyboard to display on screen.

We added the following two functions to our AppDelegate. The 'inputAccessoryView' variable is a UIView* we have declared in our app delegate:

//This function responds to all textFieldBegan editing // we need to add an accessory view and use that to force the keyboards frame // this way the keyboard appears when the scanner is attached -(void) textFieldBegan: (NSNotification *) theNotification {     UITextField *theTextField = [theNotification object];     //  NSLog(@"textFieldBegan: %@", theTextField);      if (!inputAccessoryView) {         inputAccessoryView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, navigationController.view.frame.size.width, 1)];     }      theTextField.inputAccessoryView = inputAccessoryView;      [self performSelector:@selector(forceKeyboard) withObject:nil afterDelay:0]; }  //Change the inputAccessoryView frame - this is correct for portrait, use a different // frame for landscape -(void) forceKeyboard {     inputAccessoryView.superview.frame = CGRectMake(0, 759, 768, 265); } 

Then in our applicationDidFinishLaunching we added this notification observer so we would get an event anytime a text field began editing

    //Setup the textFieldNotifications     [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(textFieldBegan:) name:UITextFieldTextDidBeginEditingNotification object:nil]; 

Hope that helps!

Answer 2

There’s no way to do this with the current SDK. Please let Apple know via the Bug Reporter.