I am relatively new to jQuery, and I would like to be able to show a menu on mouseover.
Here is the HTML content:
<td class ="comment_div"> <?php echo("$comment_data['comment']); ?> <br/>
<span class="comment_actions"> Approve | Delete | Spam | Edit</span>
</td>
Then the jQuery code:
$("comment_div").hover(
function() { $(".comment_actions").show(); },
function() { $(".comment_actions").hide(); }
);
This works except for I'm pulling multiple comments out and this only will show the menu on the first div no matter what "comment" is hovered. I would like to have the menu show only for the comment that is currently being hovered over. I think I need to use "$this" to make this work, but I am not sure how.
If I'm reading that correctly, the format should be-
$(".comment_div").hover(
function() { $(this).children(".comment_actions").show(); },
function() { $(this).children(".comment_actions").hide(); }
);
Something like this works for me:
<script>
$(document).ready(function() {
$(".container").hover(
function() { $(this).children('.comment_actions').show(); },
function() { $(this).children('.comment_actions').hide(); }
);
});
</script>
<style>
</style>
<table border="1">
<tr>
<td class ="container"><br/>
asd<span class="comment_actions">Approve | Delete</span>
</td>
<td class ="container"><br/>
asd <span class="comment_actions">Approve | Delete</span>
</td>
<td class ="container"><br/>
asd<span class="comment_actions"> Approve| Delete</span>
</td>
</tr>
</table>
However, the issue you'll face is hover actions over a div that has display: none; set
. You might want to consider wrapping it in something that's mouse sensitive, and then displaying/hiding children instead.
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