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This is elementary, but my googling just doesn't cut it. I know I have to do something else to shift the values of an array one by one, but the below coding gives me the same values for items[k] to items[infinity] all equaling items[k]. What I don't understand is how to preserve the original k+1 value while I copy the k value into the k+1 slot.
if ( i < numItems) //if i is inside the used boundaries of the array
{
for (int k = i; k < numItems; k++) //shift the array values from point i
{
double temp = 0.0;
temp = items[k];
items[k+1] = temp;
}
items[i] = value; //and insert value into i
}
Does it has to be a recursive method?
583
An array is said to be right rotated if all elements of the array are moved to its right by one position. One approach is to loop through the array by shifting each element of the array to its next position. The last element of the array will become the first element of the rotated array.
The array can be left rotated by shifting its elements to a position prior to them which can be accomplished by looping through the array and perform the operation arr[j] = arr[j+1]. The first element of the array will be added to the last of rotated array.
Shift and Unshift are also both destructive methods, meaning they too will destructively change the array.
To shift the bits of array elements of a 2D array to the left, use the numpy. left_shift() method in Python Numpy. Bits are shifted to the left by appending x2 0s at the right of x1. Since the internal representation of numbers is in binary format, this operation is equivalent to multiplying x1 by 2**x2.
You can as well use memmove, that handles overlap of regions.
memmove(&items[k+1], &items[k], (numItems-k-1)*sizeof(double));
items[k] = value;
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