shell script to get year, date and month from YYYY-MM-DD format

Question

I am running a shell script which accepts date in "YYYY-MM-DD" format. from this date input, how can i get year, month and day separately?

Thanks for replies in advance.

Answer 1

except for processing the string as text(with grep/sed/awk/cut/...), you could do with with date command:

kent$  date -d '2013-09-06' +%Y
2013

kent$  date -d '2013-09-06' +%m
09

kent$  date -d '2013-09-06' +%d
06

Answer 2

You could do this to store them on variables with one command:

read YEAR MONTH DAY < <(date -d '2013-09-06' '+%Y %m %d')
printf "%s\n" "$YEAR" "$MONTH" "$DAY"