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shell_exec() returning null on "ls"

Tags:

linux

php

centos

So I have this code and I'm only trying to make a list of the saves in another directory where the php scrip is in xampp folder and the saves are to this path /root/files/saves:

<html> <body> <?php $output = shell_exec('ls /root/files/saves'); echo "<pre>$output</pre>"; ?> </body> </html> 

I don't know why I can't get it working on a var_dump it seems output is null I'm really confuse it should work or I just it all wrong I need some help.

like image 666
Mokmeuh Avatar asked Aug 14 '13 20:08

Mokmeuh


1 Answers

Add 2>&1 to the end of your shell command to have STDERR returned as well as STDOUT.

$output = shell_exec("ls /root/files/saves 2>&1"); 

Also, if the user running PHP doesn't have sufficient permissions to view the output in /root/, the above code will return a Permission denied error message.

Source: http://php.net/manual/en/function.shell-exec.php#28994

like image 87
Amal Murali Avatar answered Sep 27 '22 21:09

Amal Murali