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Shape Drawable Size not working

I have a very simple shape that I want to set the width of:

<shape android:shape="rectangle">
    <solid android:color="@color/orange"/>
    <size android:width="2dp"/>
</shape>

However, when I assign this to the background of a EditText it just shows an orange background instead of a rectangle of width 2dp. Why isn't setting the size working? I want to create a transparent drawable with a orange rectangle on the left side. I also have this wrapped in a selector:

<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:state_focused="true">
        <shape android:shape="rectangle">
            <solid android:color="@color/orange"/>
            <size android:width="2dp" android:height="6dp"/>
        </shape>
    </item>
    <item>
        <shape android:shape="rectangle">
            <solid android:color="@android:color/transparent"/>
        </shape>
    </item>
</selector>

I've tried adding height just to see if it would change the size. It doesn't. It's like its completely ignoring the size. WTF?

like image 805
chubbsondubs Avatar asked May 03 '12 15:05

chubbsondubs


7 Answers

For me, setting the gravity of the item to "center" solved the issue. For example:

<item android:id="@android:id/progress" android:gravity="center">
    <clip>
        <shape>
            <size android:height="2dp"/>
            <solid android:color="@color/my_color"/>
        </shape>
    </clip>
</item>
like image 166
Simple UX Apps Avatar answered Sep 24 '22 13:09

Simple UX Apps


It can work with a foreground. It seems like you can't set a background's gravity. But you can on a foreground. I checked API 21, 23 and 24 (well, with the Studio design preview) and the following places a solid circle dot on the ImageView.

<shape android:shape="oval" xmlns:android="http://schemas.android.com/apk/res/android">
    <solid android:color="@color/colorPrimary" />
    <size android:height="8dp" android:width="8dp" />
</shape>

With the layout snippet

    <ImageView
            android:foreground="@drawable/list_new_dot"
            android:foregroundGravity="right|center_vertical"
            tools:src="@drawable/model_1_sm"
            />

UPDATE: While it appears to work in the layout design tool, it doesn't look the same in the emulator. UPDATE 2: Since this answer has a few votes, you might want to check what I actually used in order to show a new indicator dot: https://gist.github.com/CapnSpellcheck/4d4638aefd085c703b9d990a21ddc1eb

like image 20
androidguy Avatar answered Sep 23 '22 13:09

androidguy


Just to specify the user983447's answer - the size attribute does really mean a proportion. You should set the size for all shapes in your layer-list and it'll be used a as a proportion when scaling - like the layout_weight attribute of LinearLayout. So it's better to name it not a size but a weight

Below is a work-around how to implement top and bottom white lines without using the size attribute:

<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item>
        <shape>
            <solid android:color="#fff" />
        </shape>
    </item>
    <item android:top="1dp" android:bottom="1dp">
        <shape>
            <solid android:color="#888" />
        </shape>
    </item>
</layer-list>
like image 37
AlexD Avatar answered Sep 22 '22 13:09

AlexD


I found the layer-list to be very devious for a first time Androider because of the following. At first glance most would think item top,bottom,right,left attributes are FROM the top,bottom,right,left. Where a value of the following:

<item android:top="10dp">

Would net you a starting point 10dp from the top of the respective container. This is not the case. Think of it as OFF OF the top,bottom,right,left. <item android:top="10dp"> will still net you a starting point 10dp OFF OF the top, but what happens when you want to set the bottom?

<item android:bottom="20dp">

This will not get you a bottom at 20dp from the TOP, rather a bottom of 20dp OFF OF the BOTTOM of the container.

So, for example with a 100dp container, if you wanted a rectangle with a top edge starting at 20dp and a bottom edge at 40dp:

<item android:top="20" android:bottom="60dp">
like image 24
user3442825 Avatar answered Sep 21 '22 13:09

user3442825


I had similar problem.

Documentation ( http://developer.android.com/guide/topics/resources/drawable-resource.html#Shape ) says:

<size>

The size of the shape. (...)

Note: The shape scales to the size of the container View proportionate to the dimensions defined here, by default. When you use the shape in an ImageView, you can restrict scaling by setting the android:scaleType to "center".

If I understand correctly, it means that "size" tag is not for setting size but for setting proportions.

like image 20
user983447 Avatar answered Sep 24 '22 13:09

user983447


shape's size attribute will provide the value for drawable.getIntrinsicWidth & getIntrinsicHeight.

if the drawable's container(e.g. ImageView, TextView) has the layout param WRAP_CONTENT, then the container dimension will change if the drawable drawingState change.

but there are a bug in android framework in ImageView drawingState implementation

ImageView only update/resize its dimension by the drawable dimension on state_selected but don't on state_activated

like image 24
user882729 Avatar answered Sep 24 '22 13:09

user882729


The size of a shape will be ignored when you use it as a background of a View. It will work when you show it via an ImageView:

<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="rectangle">
    <solid android:color="#FF7700" />
    <size android:width="20dp" android:height="20dp"/>
</shape>

In your layout XML:

<!-- will have the size of 20dp x 20dp -->
<ImageView
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:src="@drawable/my_shape"
    />
like image 45
Cristan Avatar answered Sep 21 '22 13:09

Cristan