SHA 256 pseuedocode?

Question

I've been trying to work out how SHA-256 works. One thing I've been doing for other algorithms is I've worked out a sort of step by step pseudocode function for the algorithm.

I've tried to do the same for SHA256 but thus far I'm having quite a bit of trouble.

I've tried to work out how the wikipedia diagram works but besides the text part explaining the functions I'm not sure I've got it right.

Here's what I have so far:

Input is an array 8 items long where each item is 32 bits. Output is an array 8 items long where each item is 32 bits. Calculate all the function boxes and store those values.  |I'll refer to them by function name Store input, right shifted by 32 bits, into output.  | At this point, in the out array, E is the wrong value and A is empty Store the function boxes. | now we need to calculate out E and out A. | note: I've replaced the modulo commands with a bitwise AND 2^(32-1)  | I can't figure out how the modulus adding lines up, but I think it is like this Store (Input H + Ch + ( (Wt+Kt) AND 2^31 ) ) AND 2^31 As mod1 Store (sum1 + mod1) AND 2^31 as mod2 Store (d + mod2) AND 2^31 into output E  |now output E is correct and all we need is output A Store (MA + mod2) AND 2^31 as mod3 Store (sum0 + mod3) AND 2^31 into output A |output now contains the correct hash of input. |Do we return now or does this need to be run repeatedly? 

Did I get all of those addition modulos right? Also what are Wt and Kt? Also would this get run once and you're done or does it need to be run a certain number of times, with the output being re-used as input.

Here's the link by the way. http://en.wikipedia.org/wiki/SHA-2#Hash_function

Thanks alot, Brian