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Perhaps easiest to explain with an example:
$ echo '\&|' \&| $ echo '\&|' | while read in; do echo "$in"; done &| It seems that the read command is interpreting the backslashes in the input as escapes and is removing them. I need to process a file line by line without changing its contents and I'm not sure how to stop read from being smart here. Any ideas?
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Escape characters. Escape characters are used to remove the special meaning from a single character. A non-quoted backslash, \, is used as an escape character in Bash. It preserves the literal value of the next character that follows, with the exception of newline.
$@ refers to all of a shell script's command-line arguments. $1 , $2 , etc., refer to the first command-line argument, the second command-line argument, etc. Place variables in quotes if the values might have spaces in them.
Linux is a Unix-like operating system, so it uses the same type of slash. Mac OS X is based on BSD, another Unix-like operating system. Other consumer operating systems like Android, Chrome OS, and Steam OS are based on Linux, so they use the same type of slash.
Accrding to: http://www.vias.org/linux-knowhow/bbg_sect_08_02_01.html :
-r
If this option is given, backslash does not act as an escape character. The backslash is considered to be part of the line. In particular, a backslash-newline pair may not be used as a line continuation.
It works on my machine.
$ echo '\&|' | while read -r in; do echo "$in"; done \&| Use read -r, as per http://www.ss64.com/bash/read.html:
-r
If this option is given, backslash does not act as an escape character.
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