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Is there a sh equivalent of __FILE__, to give me the pathname of the currently executing file? POSIX solutions preferred, bash acceptable, thanks.
398
$_ (dollar underscore) is another special bash parameter and used to reference the absolute file name of the shell or bash script which is being executed as specified in the argument list. This bash parameter is also used to hold the name of mail file while checking emails. $@
BASH_SOURCE. An array variable whose members are the source filenames where the corresponding shell function names in the FUNCNAME array variable are defined. The shell function ${FUNCNAME[$i]} is defined in the file ${BASH_SOURCE[$i]} and called from ${BASH_SOURCE[$i+1]}
Try using $0.
166
This will grab both the file and the directory
# !/bin/sh
# store where we are
__PWD__=$(pwd)
# go to the current file (i.e. this file)
cd $(dirname $0)
# gives the file name, __FILE__
echo $0
__FILE__=$0
# gives the directory name, __DIR__
echo $(dirname $0)
__DIR__=$(dirname $0)
# this has been a test of the Linux filesystem; we now return you to your previous program.. :)
cd $__PWD__
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