I have a template class and I would like to have two copy ctors. One for trivial types, and another for non trivial types. The following code works (with one copy ctor):
template <typename T>
struct MyStruct
{
MyStruct()
{}
MyStruct(const MyStruct& o)
{
std::cout << "copy ";
foo(o);
}
template <typename U = T, typename std::enable_if_t<!std::is_trivial<U>::value, int> =0>
void foo(const MyStruct& o)
{
std::cout << "Non trivial" << std::endl;
}
template <typename U = T, typename std::enable_if_t<std::is_trivial<U>::value, int> =0>
void foo(const MyStruct& o)
{
std::cout << "Trivial" << std::endl;
}
MyStruct(MyStruct&& o)
{
std::cout << "Move" << std::endl;
}
};
struct MyType
{
MyType(int i){}
};
int main()
{
MyStruct<int> my1;
MyStruct<int> my2(my1);
MyStruct<MyType> mytype1;
MyStruct<MyType> mytype2(mytype1);
}
// prints
// Copy Trivial
// Copy Non trivial
When I try to do the same with two copy ctors, then it seems none of them was generated (both was SFINAEd away)
struct MyStruct
{
MyStruct()
{}
template <typename U = T, typename std::enable_if_t<!std::is_trivial<U>::value, int> =0>
MyStruct(const MyStruct& o)
{
std::cout << "Non trivial" << std::endl;
}
template <typename U = T, typename std::enable_if_t<std::is_trivial<U>::value, int> = 0>
MyStruct(const MyStruct& o)
{
std::cout << "Trivial" << std::endl;
}
MyStruct(MyStruct&& o)
{
std::cout << "Move" << std::endl;
}
};
The code does not compile:
main.cpp: In function ‘int main()’:
main.cpp:36:26: error: use of deleted function ‘constexpr MyStruct::MyStruct(const MyStruct&)’
MyStruct<int> my2(my1);
^
main.cpp:5:9: note: ‘constexpr MyStruct::MyStruct(const MyStruct&)’ is implicitly declared as deleted because ‘MyStruct’ declares a move constructor or move assignment operator
struct MyStruct
^~~~~~~~
main.cpp:39:37: error: use of deleted function ‘constexpr MyStruct::MyStruct(const MyStruct&)’
MyStruct<MyType> mytype2(mytype1);
^
main.cpp:5:9: note: ‘constexpr MyStruct::MyStruct(const MyStruct&)’ is implicitly declared as deleted because ‘MyStruct’ declares a move constructor or move assignment operator
struct MyStruct
^~~~~~~~
I tried to google for it, and I think SFINAE should work with copy constructors as well.
Please do not suggest using if constexpt
or requires concept
, this question is about SFINAE.
Thanks for any help!
Unfortunately, a template constructor can't be a default, copy or move constructor.
The signature of a copy constructor for MyStruct
is as follows
MyStruct (MyStruct const &);
This function, in your second example, is implicitly deleted because you've written an explicit move constructor.
Your template constructor, with the following signature,
template <typename, int>
MyStruct (MyStruct const &);
is (are) a valid constructor but, given is a template one, the (unfortunately deleted) real copy constructor is preferred.
Possible solution: add a real copy constructor that call (delegating constructor) the template constructor, through an additional argument.
I mean
template <typename T>
struct MyStruct
{
MyStruct()
{}
// delegating real copy constructor added
MyStruct(const MyStruct & ms0) : MyStruct{ms0, 0}
{ }
template <typename U = T,
std::enable_if_t<!std::is_trivial<U>::value, int> = 0>
MyStruct(const MyStruct& o, int = 0) // <-- added an int argument
{ std::cout << "Non trivial" << std::endl; }
template <typename U = T,
std::enable_if_t<std::is_trivial<U>::value, int> = 0>
MyStruct(const MyStruct& o, int = 0) // <-- added and int argument
{ std::cout << "Trivial" << std::endl; }
MyStruct(MyStruct&& o)
{ std::cout << "Move" << std::endl; }
};
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