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Setting an int to Infinity in C++

Tags:

c++

infinity

People also ask

How do you convert int to infinity?

Setting an int Infinity: The closest we can get by setting a variable to the maximum value that is double “a = std: numeric_limits<int>:: max();”. Which would be 231-1 if it is 32 bits wide on our implementation.

How do you input infinity in C++?

int b = anyValue; a>b is always true. Is there any feature of C++ that could make this possible? You could just use float s, which have a value that represents infinity.


Integers are inherently finite. The closest you can get is by setting a to int's maximum value:

#include <limits>

// ...

int a = std::numeric_limits<int>::max();

Which would be 2^31 - 1 (or 2 147 483 647) if int is 32 bits wide on your implementation.

If you really need infinity, use a floating point number type, like float or double. You can then get infinity with:

double a = std::numeric_limits<double>::infinity();

Integers are finite, so sadly you can't have set it to a true infinity. However you can set it to the max value of an int, this would mean that it would be greater or equal to any other int, ie:

a>=b

is always true.

You would do this by

#include <limits>

//your code here

int a = std::numeric_limits<int>::max();

//go off and lead a happy and productive life

This will normally be equal to 2,147,483,647

If you really need a true "infinite" value, you would have to use a double or a float. Then you can simply do this

float a = std::numeric_limits<float>::infinity();

Additional explanations of numeric limits can be found here

Happy Coding!

Note: As WTP mentioned, if it is absolutely necessary to have an int that is "infinite" you would have to write a wrapper class for an int and overload the comparison operators, though this is probably not necessary for most projects.


int is inherently finite; there's no value that satisfies your requirements.

If you're willing to change the type of b, though, you can do this with operator overrides:

class infinitytype {};

template<typename T>
bool operator>(const T &, const infinitytype &) {
  return false;
}

template<typename T>
bool operator<(const T &, const infinitytype &) {
  return true;
}

bool operator<(const infinitytype &, const infinitytype &) {
  return false;
}


bool operator>(const infinitytype &, const infinitytype &) {
  return false;
}

// add operator==, operator!=, operator>=, operator<=...

int main() {
  std::cout << ( INT_MAX < infinitytype() ); // true
}

This is a message for me in the future:

Just use: (unsigned)!((int)0)

It creates the largest possible number in any machine by assigning all bits to 1s (ones) and then casts it to unsigned

Even better

#define INF (unsigned)!((int)0)

And then just use INF in your code