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Set StaticResource style of a control in code behind

Let's say, I've got something like this (in MainPage.xaml):

<Page.Resources>
    <Style TargetType="TextBlock" x:Key="TextBlockStyle">
        <Setter Property="FontFamily" Value="Segoe UI Light" />
        <Setter Property="Background" Value="Navy" />
    </Style>
</Page.Resources>

Then, I would like to apply that StaticResource style to my dynamic created TextBlock (file MainPage.xaml.cs).

Is there any possibility to do this instead of doing something like this:

myTextBlock.FontFamily = new FontFamily("Segoe UI Light");
myTextBlock.Background = new SolidColorBrush(Color.FromArgb(255,0,0,128));
like image 341
kodi1911 Avatar asked Aug 30 '14 17:08

kodi1911


3 Answers

It has been more than 4 years now since this question was asked, but I want to post an answer just to share my findings.

For example if there is a Style BlueButton described in Application resource in App.xaml (Xamarin Cross-Platform App development), it can be used as follows

<?xml version="1.0" encoding="utf-8" ?><Application xmlns="http://xamarin.com/schemas/2014/forms"
         xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
         x:Class="SharedUi.App">
<Application.Resources>
    <ResourceDictionary>
        <Style x:Key="BlueButton" TargetType="Button">
            <Setter Property="TextColor" Value="White" />
            <Setter Property="FontSize" Value="20" />
            <Setter Property="BackgroundColor" Value="Blue"/>
            <Setter Property="HeightRequest" Value="70"/>
            <Setter Property="FontAttributes" Value="Bold"/>
        </Style>            
    </ResourceDictionary>
</Application.Resources></Application>

Then in the code behind

Button newButton1 = new Button
{
    Text = "Hello",
    WidthRequest = (double)15.0,
    Style = (Style)Application.Current.Resources["BlueButton"]
};
like image 81
3not3 Avatar answered Oct 08 '22 07:10

3not3


You can set, Something like this,

  TextBlock myTextBlock= new TextBlock ()
    {
        FontFamily = new FontFamily("Segoe UI Light");
        Style = Resources["TextBlockStyle"] as Style,
    };
like image 39
Sajeetharan Avatar answered Oct 08 '22 07:10

Sajeetharan


You can use this:

Style textBlockStyle;
try
{
    textBlockStyle = FindResource("TextBlockStyle") as Style;
}
catch(Exception ex)
{
    // exception handling
}

if(textBlockStyle != null)
{
    myTextBlock.Style = textBlockStyle;
}

or TryFindResource approach:

myTextBlock.Style = (Style)TryFindResource("TextBlockStyle");
like image 3
Hamlet Hakobyan Avatar answered Oct 08 '22 05:10

Hamlet Hakobyan