Serialize Python dictionary to XML [closed]

Question

There is simple JSON serialization module with name "simplejson" which easily serializes Python objects to JSON.

I'm looking for similar module which can serialize to XML.

Answer 1

There is huTools.structured.dict2xml which tries to be compatible to simplejson in spirit. You can give it hints how to wrap nested sub-structures. Check the documentation for huTools.structured.dict2et which returns ElementTree Objects instead if the strings returned by dict2xml.

>>> data = {"kommiauftragsnr":2103839, "anliefertermin":"2009-11-25", "prioritaet": 7,
... "ort": u"Hücksenwagen",
... "positionen": [{"menge": 12, "artnr": "14640/XL", "posnr": 1},],
... "versandeinweisungen": [{"guid": "2103839-XalE", "bezeichner": "avisierung48h",
...                          "anweisung": "48h vor Anlieferung unter 0900-LOGISTIK avisieren"},
... ]}

>>> print ET.tostring(dict2et(data, 'kommiauftrag',
... listnames={'positionen': 'position', 'versandeinweisungen': 'versandeinweisung'}))
'''<kommiauftrag>
<anliefertermin>2009-11-25</anliefertermin>
<positionen>
    <position>
        <posnr>1</posnr>
        <menge>12</menge>
        <artnr>14640/XL</artnr>
    </position>
</positionen>
<ort>H&#xC3;&#xBC;cksenwagen</ort>
<versandeinweisungen>
    <versandeinweisung>
        <bezeichner>avisierung48h</bezeichner>
        <anweisung>48h vor Anlieferung unter 0900-LOGISTIK avisieren</anweisung>
        <guid>2103839-XalE</guid>
    </versandeinweisung>
</versandeinweisungen>
<prioritaet>7</prioritaet>
<kommiauftragsnr>2103839</kommiauftragsnr>
</kommiauftrag>'''

Answer 2

http://code.activestate.com/recipes/415983/

http://sourceforge.net/projects/pyxser/

http://soapy.sourceforge.net/

http://www.ibm.com/developerworks/webservices/library/ws-pyth5/

http://gnosis.cx/publish/programming/xml_matters_1.txt

Answer 3

try this one. only problem I don't use attributes (because i dont like them)
dict2xml on pynuggets.wordpress.com
dict2xml on activestate

from xml.dom.minidom import Document
import copy

class dict2xml(object):
    doc     = Document()

    def __init__(self, structure):
        if len(structure) == 1:
            rootName    = str(structure.keys()[0])
            self.root   = self.doc.createElement(rootName)

            self.doc.appendChild(self.root)
            self.build(self.root, structure[rootName])

    def build(self, father, structure):
        if type(structure) == dict:
            for k in structure:
                tag = self.doc.createElement(k)
                father.appendChild(tag)
                self.build(tag, structure[k])

        elif type(structure) == list:
            grandFather = father.parentNode
            tagName     = father.tagName
            grandFather.removeChild(father)
            for l in structure:
                tag = self.doc.createElement(tagName)
                self.build(tag, l)
                grandFather.appendChild(tag)

        else:
            data    = str(structure)
            tag     = self.doc.createTextNode(data)
            father.appendChild(tag)

    def display(self):
        print self.doc.toprettyxml(indent="  ")

if __name__ == '__main__':
    example = {'auftrag':{"kommiauftragsnr":2103839, "anliefertermin":"2009-11-25", "prioritaet": 7,"ort": u"Huecksenwagen","positionen": [{"menge": 12, "artnr": "14640/XL", "posnr": 1},],"versandeinweisungen": [{"guid": "2103839-XalE", "bezeichner": "avisierung48h","anweisung": "48h vor Anlieferung unter 0900-LOGISTIK avisieren"},]}}
    xml = dict2xml(example)
    xml.display()