Sequelize select * where attribute is NOT x

Question

looking at the docs you can use model.findAll({where: {attribute: x}}). However, I want to select all attributes that are simply NOT x. I was looking into a regular expression here but that seemed like not an optimal solution.

What is the best way to do this?

Answer 1

Updated method, for modern Sequelize:

model.findAll({   where: {     someAttribute: {       [sequelize.Op.not]: 'some value'     }   } });