In socket.io 1.0 they provide a better way for this. Each socket automatically joins a default room by self id. Check documents: http://socket.io/docs/rooms-and-namespaces/#default-room
So you can emit to a socket by id with following code:
io.to(socketid).emit('message', 'for your eyes only');
In socket.io 1.0 you can do that with following code:
if (io.sockets.connected[socketid]) {
io.sockets.connected[socketid].emit('message', 'for your eyes only');
}
Update:
@MustafaDokumacı's answer contains a better solution.
@Mustafa Dokumacı and @Curious already provided enough information, I am adding how you can get socket id.
To get socket id use socket.id:
var chat = io.of("/socket").on('connection',onSocketConnected);
function onSocketConnected(socket){
console.log("connected :"+socket.id);
}
If you have used a namespace I found that the following works :
//Defining the namespace <br>
var nsp = io.of('/my-namespace');
//targeting the message to socket id <br>
nsp.to(socket id of the intended recipient).emit('private message', 'hello');
More about namespaces: http://socket.io/docs/rooms-and-namespaces/
I believe both @Curious and @MustafaDokumacı provided solutions that work well. The difference though is that with @MustafaDokumacı's solution the message is broadcasted to a room and not only to a particular client.
The difference is prominent when an acknowledgement is requested.
io.sockets.connected[socketid].emit('message', 'for your eyes only', function(data) {...});
works as expected, while
io.to(socketid).emit('message', 'for your eyes only', function(data) {...});
fails with
Error: Callbacks are not supported when broadcasting
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With