I would like to perform a self-join on a Pandas dataframe so that some rows get appended to the original rows. Each row has a marker 'i' indicating which row should get appended to it on the right.
d = pd.DataFrame(['A','B','C'], columns = ['some_col'])
d['i'] = [2,1,1]
In [17]: d
Out[17]:
some_col i
0 A 2
1 B 1
2 C 1
Desired output:
some_col i some_col_y
0 A 2 C
1 B 1 B
2 C 1 B
That is, row 2 gets appended to row 0, row 1 to row 1, row 1 to row 2 (as indicated by i).
My idea of how to go about it was
pd.merge(d, d, left_index = True, right_on = 'i', how = 'left')
But it produces something else altogether. How to do it correctly?
Instead of using merge
you can also use indexing and assignment:
>>> d['new_col'] = d['some_col'][d['i']].values
>>> d
some_col i new_col
0 A 2 C
1 B 1 B
2 C 1 B
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