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Selenium - stale element reference: element is not attached to the page

I am trying to understand why it gives an error while I am trying to display items that took from websites. I am also using google chrome for a browser.

chromeDriver.Navigate().GoToUrl("somewebsites");

chromeDriver.FindElement(By.Id("something.link.text")).Click();
chromeDriver.Manage().Timeouts().ImplicitlyWait(TimeSpan.FromSeconds(5));

And this other parts of my code

var item = chromeDriver.FindElementsByXPath("//*[starts-with(@id,\"g_1_\")]/td[3]/span");
foreach (var value in item)
{
    Console.WriteLine(value.Text); 
}

Whenever I use "chromeDriver.FindElement(By.Id("something.link.text")).Click();", it gives an error. I can't display the data that I pulled.

In the error message, It says "OpenQA.Selenium.StaleElementReferenceException: 'stale element reference: element is not attached to the page document". I checked the other posts, but I did not figure it out. How can I solve it?

As I read, selenium gives much faster response than website opening time, so it gives the error. Also, rarely, it gives that selenium cannot be located the element. Any suggestion?

EDIT: If I remove ".text" from display function, It displays "OpenQA.Selenium.Remote.RemoteWebElement". Does the problems with strings ?

EDIT2: I can hold data that I took from websites as like this:

[i]="System.Collections.ObjectModel.ReadOnlyCollection`1[OpenQA.Selenium.IWebElement]" For this, I wrote something like this:

string[] test= new string[100];

for (int i = 0; i < 100; i++)
{
     kaan[i] = driver.FindElements(By.XPath("//*[starts-with(@id,\"g_1_\")]/td[3]/span")).ToString();
}

How can I convert to the text

like image 749
Kaan Taha Köken Avatar asked Jul 09 '17 23:07

Kaan Taha Köken


2 Answers

I haven't worked in c# but have worked on java/selenium. But,I can give you the idea to overcome staleness.

Generally we will be getting the Stale Exception if the element attributes or something is changed after initiating the webelement. For example, in some cases if user tries to click on the same element on the same page but after page refresh, gets staleelement exception.

To overcome this, we can create the fresh webelement in case if the page is changed or refreshed. Below code can give you some idea.(It's in java but the concept will be same)

Example:

 webElement element = driver.findElement(by.xpath("//*[@id='StackOverflow']"));
 element.click();
 //page is refreshed
 element.click();//This will obviously throw stale exception

To overcome this, we can store the xpath in some string and use it create a fresh webelement as we go.

String xpath = "//*[@id='StackOverflow']";
driver.findElement(by.xpath(xpath)).click();
//page has been refreshed. Now create a new element and work on it
driver.findElement(by.xpath(xpath)).click();   //This works

In this case, we are collecting a group of webelements and iterating to get the text. But it seems there is some changes in the webelement after collecting the webelements and gettext throws staleness. We can use a loop and create the element on the go and get text.

for(int i = 0; i<5; i++)
{
   String value = driver.findElement(by.xpath("//.....["+i+"]")).getText);
   System.out.println(value);
}

Hope this helps you. Thanks.

like image 140
santhosh kumar Avatar answered Oct 20 '22 20:10

santhosh kumar


This type of error is usually caused by an updated DOM. I would suggest that you on all pages that contain javascript/ajax calls actually wait for those calls to finish before interacting with the site. I generally perform this wait just after the page has loaded, and when performing some kind of action that triggers javascript/ajax calls and/or updates to the DOM. In practice, this means running the below function after the page has loaded (or has been interacted with), and after that find the element you want to interact with.

public void WaitForJqueryAjax() {
        int delay = MaxdelaySeconds;
        while(delay > 0) {
            Thread.Sleep(1000);
            var jquery = (bool)(this.driver as IJavaScriptExecutor)
                .ExecuteScript("return window.jQuery == undefined");
            if(jquery) {
                break;
            }
            var ajaxIsComplete = (bool)(this.driver as IJavaScriptExecutor)
                .ExecuteScript("return window.jQuery.active == 0");
            if(ajaxIsComplete) {
                break;
            }
            delay--;
        }
    }
like image 3
Agent Shoulder Avatar answered Oct 20 '22 20:10

Agent Shoulder