I saw many topics about this subject and I have been unsuccessful in understanding how to do it.
For example, if I have this table:
+------+-------+-------+
| id | name | class |
+------+-------+-------+
| 5 | test | one |
| 10 | test2 | one |
| 12 | test5 | one |
| 7 | test6 | two |
+------+-------+-------+
and I want to show only X random rows from class "one", how can I do that?
NOTE: it's a big table, so I don't want to use ORDER BY RAND
.
To select last two rows, use ORDER BY DESC LIMIT 2.
Below SQL statement is to display the defined number of random rows from a table using RAND() function: Query: SELECT * FROM table_name order by RANDOM() LIMIT n; In table_name mention your Table Name and in the place of 'n' give how many rows to be fetched.
If you need the rows in a random order, grab the required number of rows and then use PHP's shuffle function on the array of rows returned. There can be quite a performance penalty with using ORDER BY RAND() in a query, depending on how many records there are.
The ORDER BY RAND()
solution that most people recommend doesn't scale to large tables, as you already know.
SET @r := (SELECT FLOOR(RAND() * (SELECT COUNT(*) FROM mytable)));
SET @sql := CONCAT('SELECT * FROM mytable LIMIT 1 OFFSET ', @r);
PREPARE stmt1 FROM @sql;
EXECUTE stmt1;
I cover this and other solutions in my book, SQL Antipatterns: Avoiding the Pitfalls of Database Programming.
If you want to do this with PHP, you could do something like this (not tested):
<?php
$mysqli->begin_transaction();
$result = $mysqli->query("SELECT COUNT(*) FROM mytable")
$row = $result->fetch_row();
$count = $row[0];
$offset = mt_rand(0, $count);
$result = $mysqli->query("SELECT * FROM mytable LIMIT 1 OFFSET $offset");
...
$mysqli->commit();
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