Ok, here's my table:
product_id version_id update_id patch_id
1 1 0 0
1 1 1 0
1 1 1 1
1 1 2 0
1 1 2 1
2 1 0 0
2 2 0 0
2 3 0 0
2 3 0 1
3 1 0 0
3 1 0 1
Now I want to select the latest version of a product, so the version with the highest update_id & patch_id.
For example, the latest version of
I was trying all kinds of stuff with GROUP BY and HAVING, tried subqueries, but I still can't figure out a way to accomplish this.
Can anybody help me out to find the right query, or should I think of writing a php function for this?
Edit
Some additional info: - The columns together are the primary key (there are more colums, but for this problem they don't matter) - None of the columns is auto-increment
This is the table:
CREATE TABLE IF NOT EXISTS `db`.`patch` (
`product_id` INT NOT NULL ,
`version_id` INT NOT NULL ,
`update_id` INT NOT NULL ,
`patch_id` INT NOT NULL
PRIMARY KEY (`product_id`, `version_id`, `update_id`, `patch_id`) ,
INDEX `fk_patch_update1` (`product_id` ASC, `version_id` ASC, `update_id` ASC) )
Edit 2
Flagged as duplicate, it is not: The other question looks for records higher than a value for any of the three different columns.
In this question we look for the highest version number grouped by the product_id.
Edit 3
rgz's answer tells me again that this is a duplicate. First of all: this question is older. Secondly, I don't think the answer is the same.
rgz suggests using the following query:
SELECT product_id, GREATEST(version_id, update_id, patch_id) AS latest_version FROM patch.
GREATEST(1,2,3) returns 3, right? Wat if we have these values:
product_id version_id update_id patch_id
1 1 0 0
1 1 2 8
1 3 0 0
As I understand, this query wil return:
product_id latest_version
1 1
1 8
1 3
But it should return:
product_id version_id update_id patch_id
1 3 0 0
I don't think GREATEST could help. If you think it will, please prove me wrong.
The MySQL Solution If you're working with MySQL, you can combine MAX() with the GREATEST() function to get the biggest value from two or more fields. Here's the syntax for GREATEST: GREATEST(value1,value2,...) Given two or more arguments, it returns the largest (maximum-valued) argument.
Discussion: To find the max value of a column, use the MAX() aggregate function; it takes as its argument the name of the column for which you want to find the maximum value. If you have not specified any other columns in the SELECT clause, the maximum will be calculated for all records in the table.
To select multiple columns from a table, simply separate the column names with commas! For example, this query selects two columns, name and birthdate , from the people table: SELECT name, birthdate FROM people; Sometimes, you may want to select all columns from a table.
This is one example of when unique identifers come in useful.
Imagine you have an autoincrememnting ID field, you can then find the id you want for each product by using a correlated sub-query...
SELECT
*
FROM
yourTable
WHERE
id = (
SELECT id
FROM yourTable AS lookup
WHERE lookup.product_id = yourTable.product_id
ORDER BY version_id DESC, update_id DESC, patch_id DESC
LIMIT 1
)
The equivalent without a unique identifer requires multiple correlated sub-queries...
SELECT
*
FROM
yourTable
WHERE
version_id = (
SELECT MAX(version_id)
FROM yourTable AS lookup
WHERE lookup.product_id = yourTable.product_id
)
AND update_id = (
SELECT MAX(update_id)
FROM yourTable AS lookup
WHERE lookup.product_id = yourTable.product_id
AND lookup.version_id = yourTable.version_id
)
AND patch_id = (
SELECT MAX(patch_id)
FROM yourTable AS lookup
WHERE lookup.product_id = yourTable.product_id
AND lookup.version_id = yourTable.version_id
AND lookup.update_id = yourTable.update_id
)
This would be significantly slower than on a table with a unique identifier column.
Another alternative (without a unique identifier) is to self-join on different levels of aggregation.
SELECT
yourTable.*
FROM
(SELECT product_id, MAX(version_id) AS max_version_id FROM yourTable GROUP BY product_id) AS version
INNER JOIN
(SELECT product_id, version_id, MAX(update_id) AS max_update_id FROM yourTable GROUP BY product_id, version_id) AS update
ON update.product_id = version.product_id
AND update.version_id = version.max_version_id
INNER JOIN
(SELECT product_id, version_id, updatE_id, MAX(patch_id) AS max_patch_id FROM yourTable GROUP BY product_id, version_id) AS patch
ON patch.product_id = update.product_id
AND patch.version_id = update.version_id
AND patch.update_id = update.max_update_id
INNER JOIN
yourTable
ON yourTable.product_id = patch.product_id
AND yourTable.version_id = patch.version_id
AND yourTable.update_id = patch.update_id
AND yourTable.patch_id = patch.max_patch_id
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