Selecting elements of a Python dictionary greater than a certain value

Question

I need to select elements of a dictionary of a certain value or greater. I am aware of how to do this with lists, Return list of items in list greater than some value.

But I am not sure how to translate that into something functional for a dictionary. I managed to get the tags that correspond (I think) to values greater than or equal to a number, but using the following gives only the tags:

[i for i in dict if dict.values() >= x] 

Answer 1

.items() will return (key, value) pairs that you can use to reconstruct a filtered dict using a list comprehension that is feed into the dict() constructor, that will accept an iterable of (key, value) tuples aka. our list comprehension:

>>> d = dict(a=1, b=10, c=30, d=2) >>> d {'a': 1, 'c': 30, 'b': 10, 'd': 2} >>> d = dict((k, v) for k, v in d.items() if v >= 10) >>> d {'c': 30, 'b': 10} 

If you don't care about running your code on python older than version 2.7, see @opatut answer using "dict comprehensions":

{k:v for (k,v) in dict.items() if v > something} 

Answer 2

While nmaier's solution would have been my way to go, notice that since python 2.7+ there has been a "dict comprehension" syntax:

{k:v for (k,v) in dict.items() if v > something} 

Found here: Create a dictionary with list comprehension in Python. I found this by googling "python dictionary list comprehension", top post.

Explanation

• { .... } includes the dict comprehension
• k:v what elements to add to the dict
• for (k,v) in dict.items() this iterates over all tuples (key-value-pairs) of the dict
• if v > something a condition that has to apply on every value that is to be included