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i need to select the value of second to last input selectable element:
<tr><td><select class="x">...</select></td></tr>
<tr><td><select class="x">...</select></td></tr>
<tr><td><select class="x">...</select></td></tr>
The select input tag are inside tr tags.
If I use $("select.x").last(), jQuery select the last element. I need to select second to last.
325
To get the second to last element in an array, call the at() method on the array, passing it -2 as a parameter, e.g. arr.at(-2) . The at method returns the array element at the specified index.
You need to use "nth-last-child(2)" of jquery, this selects the second last element.
The :last selector selects the last element. Note: This selector can only select one single element. Use the :last-child selector to select more than one element (one for each parent). This is mostly used together with another selector to select the last element in a group (like in the example above).
You need to use "nth-last-child(2)" of jquery, this selects the second last element.
You can check this here:
https://api.jquery.com/nth-last-child-selector/
144
The solutions with .prev() or nth-last-child() don't works.
<tr><td><a>...</a><select class="x"></select><a>...</a><td><tr>
<tr><td><a>...</a><select class="x"></select><a>...</a><td><tr>
<tr><td><a>...</a><select class="x"></select><a>...</a><td><tr>
<tr><td><a>...</a><select class="x"></select><a>...</a><td><tr>
The problem is the last().prev() functions return the the object <a> which i suppouse come first the select one.
The nth-last-of-type(2) selector instead return an empty object.
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