Select elements without any class [duplicate]

Question

I need to find, via jQuery selectors, all spans in a page that have no class.

Example:

<span class='Cool'>do not found me</span>
<span>me, me, take me please!!!</span>

Answer 1

Use :not() and the attribute not selector [att!=val] to filter out elements with a non-empty class attribute:

$('span:not([class!=""])')

jsFiddle preview

Note however that [att!=val] is a non-standard jQuery selector, which means the selector cannot be used in CSS or with document.querySelectorAll(). If you're like me, and you're a stickler for following the standards and so want to eschew non-standard jQuery selectors where possible, the following is a direct equivalent:

$('span:not([class]), span[class=""]')

This matches

• span elements that have no class attribute, and
• span elements that do have a class attribute, but only when the attribute value is empty.

In most cases, though, you should be able to get away with just the first portion:

$('span:not([class])')

You'll usually only find empty class attributes in markup generated by the application that's responsible for outputting it, or by developers who aren't paying attention.

Answer 2

See this answer to do it with css only Can I write a CSS selector selecting elements NOT having a certain class?

:not([class])

Actually, this will select anything witch do not have a .class applied to it.

I gathered a jsfiddle demo

html

<h2 class="fake-class">fake-class will be green</h2>
<h2 class="">empty class SHOULD be white</h2>
<h2>no class should be red</h2>
<h2 class="fake-clas2s">fake-class2 SHOULD be white</h2>
<h2 class="">empty class2 SHOULD be white</h2>
<h2>no class2 SHOULD be red</h2>

css

h2 {color:#fff}
:not([class]) {color:red;background-color:blue}
.fake-class {color:green}