I have the following query
select main_cat_name,cat_url from mf_main order by main_cat_name
This returns whole data of my table.Now i want to have count of the total rows of this table.I can do it using another query but how can i use them in one single query???
I want two data ONE :- the rows of the table TWO:- the count how can i have that in one single query
I tried this but it gives correct count but displays only first row of the table :
select count(cat_id),main_cat_name,cat_url from mf_main order by main_cat_name
In SQL, you can make a database query and use the COUNT function to get the number of rows for a particular group in the table. Here is the basic syntax: SELECT COUNT(column_name) FROM table_name; COUNT(column_name) will not include NULL values as part of the count.
The use of COUNT() function in conjunction with GROUP BY is useful for characterizing our data under various groupings. A combination of same values (on a column) will be treated as an individual group.
SQL SELECT statement can be used along with COUNT(*) function to count and display the data values. The COUNT(*) function represents the count of all rows present in the table (including the NULL and NON-NULL values).
We can use GROUP BY to group together rows that have the same value in the Animal column, while using COUNT() to find out how many ID's we have in each group. It returns a table with three rows (one for each distinct animal).
You can try with Group By like:
SELECT count(cat_id), main_cat_name, cat_url FROM mf_main GROUP BY main_cat_name, cat_url ORDER BY main_cat_name
Right solution i hope:
This is what you want:)
SELECT x.countt, main_cat_name, cat_url FROM mf_main, (select count(*) as countt FROM mf_main) as x ORDER BY main_cat_name
If you use mysql u have "as" like i did. For others db may be without as (like oracle)
You could try
select main_cat_name,cat_url, COUNT(*) OVER () AS total_count from mf_main order by main_cat_name
Not sure if MySQL accepts the AS
, just remove it if it does not.
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