I'm trying to write a query that would select only the rows that have events which where the only events in that year.
Eg:
Year Event
2011 A
2011 B
2012 C
2013 B
2013 D
2014 D
So, I would like to get the rows 2012 C
and 2014 D
in the results.
I tried doing a GROUP BY
on Year
, but that wouldn't let me select the Event
column.
2011 and 2013 have 2 events, so these shouldn't be in the results.
Please help.
EDIT: I could write a nested query to get the only the rows having count(Year) = 1
with GROUP BY Year
, but I'm unable to get the Event
column selected in the outer query
SELECT Year, Event from table where Year in (SELECT Year from table GROUP BY Year Having count(*) = 1) as count;
SQLRaptor also said this was an example of a GROUP BY using columns not in the SELECT list and that this could be an elegant (powerful) solution to some SQL challenges! I thought the non-generality might be something to do with the multiplication (duplicates), but had no concrete proof.
The columns in the result set of a select query with group by clause must be: an expression used as one of the group by criteria , or ... an aggregate function , or ... So, you can't do what you want to do in a single, simple query. The first thing to do is state your problem statement in a clear way, something like:
If you are familiar with GROUP BY, you should recall the following general rule: each column in the SELECT statement should either be called in an aggregate function or be in the GROUP BY clause.
Finally, now that you’re firmly grounded in the key rule of the GROUP BY clause – namely, all non-aggregated columns from the SELECT statement should be in GROUP BY – it turns out that this is not always the case! Intrigued? Read this article to learn more.
There is no need for using a subquery or nested query. You can simply GROUP By Year
field and use HAVING COUNT(Year)=1
to find the required rows. So, the applicable query will be:
SELECT Year, Event
FROM table_name
GROUP BY Year
HAVING COUNT(Year)=1
You can find the executable solution sample at:
http://sqlfiddle.com/#!9/b47044/11
Logic:
When you group by Year
it aggregates all rows with same year. So, count will be 2
for 2011
.
You can check this by running:
SELECT Year, Event, COUNT(Year) as event_count
FROM table_name
GROUP BY Year
You can see this intermediate step in execution, at: http://sqlfiddle.com/#!9/b47044/10
This above solution will only work for MySQL version < 5.7. For higher versions find the solution below.
For 5.7 and greater the ONLY_FULL_GROUP_BY SQL mode is enabled by default so this will fail. Either you can update this mode( Refer answers under SELECT list is not in GROUP BY clause and contains nonaggregated column .... incompatible with sql_mode=only_full_group_by ) or alternatively you can use ANY_VALUE()
function to refer to the non-aggregated column, so update query that will work in MySQL 5.7 and greater is:
SELECT Year, ANY_VALUE(Event)
FROM table_name
GROUP BY Year
HAVING COUNT(Year)=1;
You can find executable example at: https://paiza.io/projects/e/tU-7cUoy3hQUk2A7tFfVJg
Reference: https://docs.oracle.com/cd/E17952_01/mysql-5.7-en/miscellaneous-functions.html#function_any-value
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