Second Select Won't POST

Question

I have a form that includes two <select> tags:

<li>
    <label for="uname">Select User : </label>
    <select id="uname" name="uname">
        <option value="3">Kaine McAuley</option>
    </select>
</li>
<li>
    <label for="uweek">Week Number : </label>
    <select id="uweek" name="uweek">
        <option value="1">Week 1</option>
        <option value="2">Week 2</option>
        <option value="3">Week 3</option>
        <option value="4">Week 4</option>
        <option value="5">Week 5</option>
        <option value="6">Week 6</option>
        <option value="7">Week 7</option>
        <option value="8">Week 8</option>
        <option value="9">Week 9</option>
        <option value="10">Week 10</option>
        <option value="11">Week 11</option>
        <option value="12">Week 12</option>
    </select>
</li>

That's how it comes out in the browser. I have echo'd the contents of $_POST and uweek doesn't exist in there. However, uname does!

My actual PHP code that creates the form is as follows:

echo '<h2>Update Users</h2><form action="" method="post">
    <ul style="list-style: none;">
            <li>
            <label for="uname">Select User : </label>
            <select id="uname" name="uname">';
while($r = mysqli_fetch_assoc($sql))
{
    switch($r['Username'])
    {
        case 'Mike':
        case '3rungohan':
        case 'Test':
        case 'Jestress':break;
        default: echo '<option value="' . $r['UserID'] . '">' . $r['RealName'] . '</option>';
    }
}

echo '</select></li>
<li>
    <label for="uweek">Week Number : </label>
    <select id="uweek" name="uweek">';
    for($i=1;$i<13;$i++)
    {
        $week = "Week " . $i;
        echo '<option value="' . $i . '">' . $week . '</option>';
    }
    echo '</select>
</li>
<li>
    <label for="uaims">Week Aims : </label><br />
    <textarea id="uaims" name="uaims" rows="4" cols="40" required="required"></textarea>
</li>
<li>
    <label for="upros">Week Progress : </label><br />
    <textarea id="upros" name="upros" rows="4" cols="40" required="required"></textarea>
</li>
<li>
    <label for="unote">Week Notes : </label><br />
    <textarea id="unote" name="unote" rows="4" cols="40" required="required" placeholder="If no notes, just enter: No notes"></textarea>
</li>
<li>
    <input type="submit" value="Submit" />
</li>
</ul>
</form>';

Results of print_r($_POST);

Array ( [uname] => 3 [uaims] => Aims [upros] => Nope [unote] => No )

Similar results from var_dump($_REQUEST);

array(4) { ["uname"]=> string(1) "3" ["uaims"]=> string(4) "Aims" ["upros"]=> string(4) "Nope" ["unote"]=> string(2) "No" }

Once $_POST executes and goes through, my code (at the top of the php document): Sorry for the endless queries I needed several rounds of info from different tables.

if(!empty($_POST['uname']))
{
    foreach($_POST as $k => $v) {$up[$k] = $v;}
    $sql2 = mysqli_query($link, "SELECT * FROM jestresstracker WHERE UserID='" . mysqli_real_escape_string($link, $up['uname']) ."' ORDER BY WeekNum DESC LIMIT 1");
    $temp = mysqli_fetch_assoc($sql2);
    $sql3 = mysqli_query($link, "SELECT * FROM jestress_users WHERE UserID='" . mysqli_real_escape_string($link, $up['uname']) ."' LIMIT 1");
    $r = mysqli_fetch_assoc($sql3);
    foreach($r as $k => $v) {$User[$k] = $v;}
    if(!empty($temp['WeekNum']))
    {
        if($up['uweek']<=$temp['WeekNum']) {$result = "Error. Update already set for this week. Week Num: " . $temp['WeekNum'];}
    }
    else {
        $ins = mysqli_query($link, "INSERT INTO jestresstracker (UserID, WeekNum, WeekAims, WeekPro, Updated, UpdatedBy, Notes) VALUES('" . mysqli_real_escape_string($link, $up['uname']) . "', '" . mysqli_real_escape_string($link, $up['uweek']) . "', '" . mysqli_real_escape_string($link, nl2br($up['uaims'])) . "', '" . mysqli_real_escape_string($link, nl2br($up['upros'])) . "', NOW(), '" . mysqli_real_escape_string($link, $res['UserID']) . "', '" . mysqli_real_escape_string($link, nl2br($up['unote'])) . "')");
        if($ins) {$result = "Successfully updated " . $User['RealName'] . "'s Week " . $up['uweek'] . " post.";var_dump($_REQUEST);}
        else {$result = "Error: " . mysqli_error($link);}
    }
}

EDIT: Changing the id/name doesn't return different results.

Answer 1

The best friend here in such situation is firebug or any network analysis tool..

Check the headers and make sure that concerned field is indeed posted through..

I think this may help greatly..