I have a dataframe containing a sentence per row. I need to search through these sentences for the occurence of certain words. This is how I currently do it:
import pandas as pd
p = pd.DataFrame({"sentence" : ["this is a test", "yet another test", "now two tests", "test a", "no test"]})
test_words = ["yet", "test"]
p["word_test"] = ""
p["word_yet"] = ""
for i in range(len(p)):
for word in test_words:
p.loc[i]["word_"+word] = p.loc[i]["sentence"].find(word)
This works as intended, however, is it possible to optimize this? It runs fairly slow for large dataframes
You can use str.find
p['word_test'] = p.sentence.str.find('test')
p['word_yet'] = p.sentence.str.find('yet')
sentence word_test word_yet word_yest
0 this is a test 10 -1 -1
1 yet another test 12 0 0
2 now two tests 8 -1 -1
3 test a 0 -1 -1
4 no test 3 -1 -1
IIUC, use a simple list comprehension and call str.find
for each word:
u = pd.DataFrame({
# 'word_{}'.format(w)
f'word_{w}': df.sentence.str.find(w) for w in test_words}, index=df.index)
u
word_yet word_test
0 -1 10
1 0 12
2 -1 8
3 -1 0
4 -1 3
pd.concat([df, u], axis=1)
sentence word_yet word_test
0 this is a test -1 10
1 yet another test 0 12
2 now two tests -1 8
3 test a -1 0
4 no test -1 3
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