Search and match one or more words in search query in Wordpress

Question

I'm trying to make search results to show different structure depending of the words in search.

What I want is to catch words - apple, plum, tree and if some of this words or all of them are searched to show div1 else div2.

What I've tried so far is

    $words_array = explode(' ', $_GET['s']);
    $words = 'apple plum tree';

    if(in_array($words, $words_array)) {      

         echo 'div1';
    } else {
         echo 'div2';
      }

This doesn't work as is return div2 when I search one of the words or combination of them.

If I make it like this

    $words_array = explode(' ', $_GET['s']);

    if(in_array('apple', $words_array)) {      

         echo 'div1';
    } else {
         echo 'div2';
      }

and search for apple is return correct result div1.

UPDATE: print_r($words_array);

Array ( [0] => apple [1] => and [2] => tree

print_r($words);

Array ( [0] => apples [1] => apple [2] => tree [3] => plum )

Answer 1

in_array() function requires first parameter to be string.

in_array ( mixed $needle , array $haystack [, bool $strict = FALSE ] ) : bool

You are passing array as first parameter.

That is why the function is not returning correct value. And second parameter is the array to be searched.

Initialise a variable $divOneFlag with default FALSE.

Please loop over $words and then call in_array() in the loop.

If word is found, set it to TRUE.

If variable is TRUE, echo 'div1';

Else echo 'div2';

<?php
$words_array = ['apple', 'and', 'tree'];
$words = ['apples', 'apple', 'tree', 'plum'];
$divOneFlag = FALSE;
if (! empty($words)) {
 foreach ($words as $word) {
  if (in_array($word, $words_array)) {
   $divOneFlag = TRUE;
  }
 }
}
if ($divOneFlag) {
 echo 'div1';
}
else {
 echo 'div2';
}

Working Demo: