So I was hoping someone could help me out with something that seemed simple.
I have a grid template set up with ads coming in, in various locations. Causing the structure of the code to be a bit complicated. Basically right now for me to get it looking just right, I am using quite a bit of &:nth-child selectors to remove / ad margins at various breakpoints.
Instead of me writing out things such as:
&:nth-child( 3 ),
&:nth-child( 10 ),
&:nth-child( 13 ),
&:nth-child( 17 ),
&:nth-child( 20 ),
&:nth-child( 23 ),
&:nth-child( 26 ),
&:nth-child( 30 ),
&:nth-child( 33 ),
&:nth-child( 37 ),
&:nth-child( 43 ) {
margin-right: $gutter-width;
}
I have been trying to create a mixing that would allow me to pass an array of integers and for the css to spit out what I showed above by calling something along the lines of
@include nth-children( 3, 10, 13, 17, 20...) {
margin-right: $gutter-width;
}
The only issue is that I also would need to be able to pass an equation as part of that list ( 20n - 5 ) or whatever the case may be.
I have tried a few things but can't seem to even get it close
@mixin nth-children($nths) {
@for $i from 1 through length($nths) {
&:nth-child(#{$i}) {
@content;
}
}
}
I want to prevent of creating a list first since the values will be ever changing on multiple different screen sizes and page layouts.
You can pass in a positive number as an argument to :nth-child() , which will select the one element whose index inside its parent matches the argument of :nth-child() . For example, li:nth-child(3) will select the list item with an index value 3; that is, it will select the third list item.
Writing Complex :nth-child() Selectors It works exactly the same as :nth-child except that it starts from the end of the parent. For example, you can select the first three children of a parent by using the selector :nth-child(-n + 3) . You can use :nth-last-child(-n + 3) to select the last three.
Definition and Usage. The :nth-child(n) selector matches every element that is the nth child of its parent. n can be a number, a keyword (odd or even), or a formula (like an + b). Tip: Look at the :nth-of-type() selector to select the element that is the nth child, of the same type (tag name), of its parent.
The :nth-child selector allows you to select one or more elements based on their source order, according to a formula. It is defined in the CSS Selectors Level 3 spec as a “structural pseudo-class”, meaning it is used to style content based on its relationship with parent and sibling elements.
This works:
$gutter-width: 12px;
$array: ("2n+1", "1", "2");
div {
@each $i in $array {
&:nth-child( #{$i} ) {
margin-right: $gutter-width;
}
}
}
@function nth-child-adder($item) {
@return "&:nth-child(" + $item + ")";
}
@function nth-child-namer($array) {
$x: "";
@each $i in $array {
@if $x != "" {
$x: append($x, "," + nth-child-adder($i));
}
@else{
$x: append($x, nth-child-adder($i));
}
}
@return $x;
}
$gutter-width: 12px;
$array: ("2n+1", "1", "2");
div {
#{nth-child-namer($array)} {
margin-right: $gutter-width;
}
}
the following mixin should work using @each
:
@mixin nth-children($points...) {
@each $point in $points {
&:nth-child(#{$point}) {
@content;
}
}
}
/* example call */
$gutter-width: 5px;
div {
@include nth-children( 3, 10, 13, 17, 20, "2n + 1") {
margin-right: $gutter-width;
}
}
you can use "list..." - depending on your precompiler version). I made a small codepen for it: http://codepen.io/anon/pen/AXYRNB
$params: (1, 2, 3, 4);
$paramsLength: length($params);
@function item($item) {
@return nth($params, $item);
}
@mixin nth-children($params...) {
@for $i from 1 through $paramsLength {
&:nth-child( #{item($i)} ) {
margin-left: 2em;
}
}
}
ul {
@include nth-children($params);
}
for more information, have a look a this: https://www.sitepoint.com/sass-multiple-arguments-lists-or-arglist/.
PS: this doesn't solve your issue with the "equation" - I don't really think that it's possible :-)
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